The Guide for Add Math Project Work F4 : SHEEP PEN
Solution
a.) Using length and width
A = 1400
b.) Method 1 : Using Calculus (differentiation)
Method 2 : Graphical Method
From (b) : A =
Construct table x=40, 41, …, 49, A=
Plot graph area A versus Length x
Construct table x= 44.5, 44.6, …, 45.5, A=
Plot graph area A versus Length x
From both table and graph, area is maximum when x=45, so y =
Method 3 : Completing the Square
c.) (i) ………….
………….
(ii) Method 1 : Using Calculus (differentiation)
Method 2 : Graphical Method
From (c) A =
Construct table x = 25, 26, ……, 35, A =
Plot graph Area versus Length
Construct table x= 29.5, 29.6,….., 30.5., A=
Plot graph Area versus Length
From both table and graph, area maximum when x=
Thus, enclosed area is maximum when length = 22.5m, and width = 30m
Method 3 : Completing square method
d.) …………….
y =
so area A =
Method 1 : Using calculus (differentiation)
Method 2 : Graphical method
From (d) , A=
Construct table x= 20.0, 2.5, ….24.5, A=
Plot the graph area versus length
Construct table x= 22.1, 22.2, …. 23.0, A =
Plot the graph area versus length
From the both table and graph, total maximum area is 1012.5
Method 3 : completing square
Further investigation
1 Rectangular sheep pen
Length =
2 Rectangular sheep pens
Sum of length =
3 Rectangular sheep pens
Sum of length =
By induction , sum of length n rectangular sheep pens =
Total area, A=
No comments:
Post a Comment